feat: Finding no. of digits in a Number

math/finding_number_of_Digits_in_a_Number.cpp

@@ -0,0 +1,48 @@
+/**
+ * @author [ANSHUMAAN](https://github.com/amino19)
+ * @file [Program to count digits in an
+ * integer](https://www.geeksforgeeks.org/program-count-digits-integer-3-different-methods)
+ *
+ * @brief Finding number of Digits in a Number
+ * @details It is a very basic math of finding number of digits in a given
+ * number i.e, we can use it by inputting values whether it can be a
+ * positive/negative value, lets say integer. There is also second method to do
+ * it with, by using "K = floor(log10(N) + 1)", but its only applicable for
+ * numbers (not integers).
+ * For more details, refer Algorithms-Explanation
+ */
+
+#include <cassert>   /// for assert
+#include <iostream>  /// for IO operations
+
+/**
+ * @brief Main function
+ * @returns 0 on exit
+ */
+int main() {
+    /* Initialize 'n' & 'count' by 0 */
+    int n = 0;
+    int count = 0;
+
+    /* 'cout' to ask input from user..
+     * 'cin' to taking integer as input..
+     */
+    std::cout << "Enter an integer: ";
+    std::cin >> n;
+
+    /* iterate until n becomes 0
+     *  remove last digit from n in each iteration
+     *  increase count by 1 in each iteration */
+    while (n != 0) {
+        /* we can also use: n = n/10 */
+        n /= 10;
+        /*  each time while loop running, count will
+         *  be increment by 1.
+         */
+        ++count;
+    }
+
+    std::cout << "Number of digits: " << count;
+
+    return 0;
+}