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bpo-16637: libpython: interpret string as integer literal #15232
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Tools/gdb/libpython.py
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@@ -1392,7 +1392,7 @@ def write_repr(self, out, visited): | |||
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def int_from_int(gdbval): | |||
return int(str(gdbval)) | |||
return int(str(gdbval), 0) |
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Can one not simply call int
on integer-type GDB values?
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You mean something like
return int(str(gdbval), 0) | |
return int(gdbval.cast(gdb.lookup_type('long'))) |
?
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Yes, but do you have to do the cast
?
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I think so - but to be sure I have to verify it. Will update my branch if it works.
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I've updated my branch. Seems a simple int
call is enough - thanks (I assume this only holds if the gdbvalue has the right type).
This fixes the exception '`ValueError: invalid literal for int() with base 10` if `str(gdbval)` returns a hexadecimal value (e.g. '0xa0'). This is the case if the output-radix is set to 16 in gdb. See https://sourceware.org/gdb/onlinedocs/gdb/Numbers.html for more information.
Thanks @marc1006 for the PR, and @benjaminp for merging it 🌮🎉.. I'm working now to backport this PR to: 3.8. |
GH-16345 is a backport of this pull request to the 3.8 branch. |
…dbvalue (GH-15232) This fixes the exception '`ValueError: invalid literal for int() with base 10` if `str(gdbval)` returns a hexadecimal value (e.g. '0xa0'). This is the case if the output-radix is set to 16 in gdb. See https://sourceware.org/gdb/onlinedocs/gdb/Numbers.html for more information. (cherry picked from commit 6f53d34) Co-authored-by: Marc Hartmayer <[email protected]>
This fixes the exception
ValueError: invalid literal for int() with base 10
if
str(gdbval)
returns a hexadecimal value (e.g. '0xa0').See https://docs.python.org/3/library/functions.html#int for more information.
https://bugs.python.org/issue16637