test/lvol: lower size of bdev in test case 700

Using lower size of bdev might speed up test a little bit
and is enough for this case.

Change-Id: Iaba1b8a771aef58c7b26a880cd351c2ec33f27f2
Signed-off-by: Karol Latecki <[email protected]>
Reviewed-on: https://review.gerrithub.io/399655
Reviewed-by: Pawel Kaminski <[email protected]>
Tested-by: SPDK Automated Test System <[email protected]>
Reviewed-by: Jim Harris <[email protected]>
Reviewed-by: Daniel Verkamp <[email protected]>
Reviewed-by: Shuhei Matsumoto <[email protected]>

test/lvol/test_cases.py

@@ -956,9 +956,9 @@ def test_case700(self):
                                                    uuid_store,
                                                    self.cluster_size)
 
-        # size = approx 10% of total NVMe disk size
+        # size = approx 2% of total NVMe disk size
         _ = self.c.get_lvol_stores()[0]
-        size = int(_["free_clusters"] / 10)
+        size = int(_["free_clusters"] / 50)
 
         for i in range(5):
             uuid_bdev = self.c.construct_lvol_bdev(uuid_store,

test/lvol/test_plan.md

@@ -675,7 +675,7 @@ Steps:
 - construct lvol store on NVMe bdev
 - using get_lvol_stores command verify lvol store was correctly created
 - construct five lvol bdevs on previously created lvol store;
-  each lvol bdev size is approximately equal to 10% of total lvol store size
+  each lvol bdev size is approximately equal to 2% of total lvol store size
   (approximately because of the lvol metadata which consumes some of the space)
 - using get_bdevs command verify lvol bdevs were correctly created
 - shutdown vhost application by sending SIGTERM signal