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feat: add solutions to lcof2 problem: No.101
lcof2 No.101.Partition Equal Subset Sum
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,20 @@ | ||
class Solution { | ||
public: | ||
bool canPartition(vector<int>& nums) { | ||
int s = 0; | ||
for (int x : nums) s += x; | ||
if (s % 2 != 0) return false; | ||
int m = nums.size(), n = (s >> 1) + 1; | ||
vector<bool> dp(n); | ||
dp[0] = true; | ||
if (nums[0] < n) dp[nums[0]] = true; | ||
for (int i = 1; i < m; ++i) | ||
{ | ||
for (int j = n - 1; j >= nums[i]; --j) | ||
{ | ||
dp[j] = dp[j] || dp[j - nums[i]]; | ||
} | ||
} | ||
return dp[n - 1]; | ||
} | ||
}; |
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,21 @@ | ||
func canPartition(nums []int) bool { | ||
s := 0 | ||
for _, x := range nums { | ||
s += x | ||
} | ||
if s%2 != 0 { | ||
return false | ||
} | ||
m, n := len(nums), (s>>1)+1 | ||
dp := make([]bool, n) | ||
dp[0] = true | ||
if nums[0] < n { | ||
dp[nums[0]] = true | ||
} | ||
for i := 1; i < m; i++ { | ||
for j := n - 1; j >= nums[i]; j-- { | ||
dp[j] = dp[j] || dp[j-nums[i]] | ||
} | ||
} | ||
return dp[n-1] | ||
} |
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,23 @@ | ||
class Solution { | ||
public boolean canPartition(int[] nums) { | ||
int s = 0; | ||
for (int x : nums) { | ||
s += x; | ||
} | ||
if (s % 2 != 0) { | ||
return false; | ||
} | ||
int m = nums.length, n = (s >> 1) + 1; | ||
boolean[] dp = new boolean[n]; | ||
dp[0] = true; | ||
if (nums[0] < n) { | ||
dp[nums[0]] = true; | ||
} | ||
for (int i = 1; i < m; ++i) { | ||
for (int j = n - 1; j >= nums[i]; --j) { | ||
dp[j] = dp[j] || dp[j - nums[i]]; | ||
} | ||
} | ||
return dp[n - 1]; | ||
} | ||
} |
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,16 @@ | ||
class Solution: | ||
def canPartition(self, nums: List[int]) -> bool: | ||
s = sum(nums) | ||
if s % 2 != 0: | ||
return False | ||
|
||
m, n = len(nums), (s >> 1) + 1 | ||
dp = [False] * n | ||
dp[0] = True | ||
if nums[0] < n: | ||
dp[nums[0]] = True | ||
|
||
for i in range(1, m): | ||
for j in range(n - 1, nums[i] - 1, -1): | ||
dp[j] = dp[j] or dp[j - nums[i]] | ||
return dp[-1] |
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