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closures.md

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Closures and first-class functions

Closures and first-class and higher order functions are a core part of Rust. In C and C++ there are function pointers (and those weird member/method pointer things in C++ that I never got the hang of). However, they are used relatively rarely and are not very ergonomic. C++11 introduced lambdas, and these are pretty close to Rust closures, in particular they have a very similar implementation strategy.

To start with, I want to establish some intuition for these things. Then, we'll dive in to the details.

Lets say we have a function foo: pub fn foo() -> u32 { 42 }. Now let's imagine another function bar which takes a function as an argument (I'll leave bar's signature for later): fn bar(f: ...) { ... }. We can pass foo to bar kind of like we would pass a function pointer in C: bar(foo). In the body of bar we can call f as if it were a function: let x = f();.

We say that Rust has first-class functions because we can pass them around and use them like we can with other values. We say bar is a higher-order function because it takes a function as an argument, i.e., it is a function that operates on functions.

Closures in Rust are anonymous functions with a nice syntax. A closure |x| x + 2 takes an argument and returns it with 2 added. Note that we don't have to give types for the arguments to a closure (they can usually be inferred). We also don't need to specify a return type. If we want the closure body to be more than just one expression, we can use braces: |x: i32| { let y = x + 2; y }. We can pass closures just like functions: bar(|| 42).

The big difference between closures and other functions is that closures capture their environment. This means that we can refer to variables outside the closure from the closure. E.g.,

let x = 42;
bar(|| x);

Note how x is in scope in the closure.

We've seen closures before, used with iterators, and this is a common use case for them. E.g., to add a value to each element of a vector:

fn baz(v: Vec<i32>) -> Vec<i32> {
    let z = 3;
    v.iter().map(|x| x + z).collect()
}

Here x is an argument to the closure, each member of v will be passed as an x. z is declared outside of the closure, but because it's a closure, z can be referred to. We could also pass a function to map:

fn add_two(x: i32) -> i32 {
    x + 2
}

fn baz(v: Vec<i32>) -> Vec<i32> {
    v.iter().map(add_two).collect()
}

Note that Rust also allows declaring functions inside of functions. These are not closures - they can't access their environment. They are merely a convenience for scoping.

fn qux(x: i32) {
    fn quxx() -> i32 {
        x // ERROR x is not in scope.
    }

    let a = quxx();
}

Function types

Lets introduce a new example function:

fn add_42(x: i32) -> i64 {
    x as i64 + 42
}

As we saw before, we can store a function in a variable: let a = add_42;. The most precise type of a cannot be written in Rust. You'll sometimes see the compiler render it as fn(i32) -> i64 {add_42} in error messages. Each function has its own unique and anonymous type. fn add_41(x: i32) -> i64 has a different type, even though it has the same signature.

We can write less precise types, for example, let a: fn(i32) -> i64 = add_42;. All function types with the same signature can be coerced to a fn type (which can be written by the programmer).

a is represented by the compiler as a function pointer, however, if the compiler knows the precise type, it doesn't actually use that function pointer. A call like a() is statically dispatched based on the type of a. If the compiler doesn't know the precise type (e.g., it only knows the fn type), then the call is dispatched using the function pointer in the value.

There are also Fn types (note the capital 'F'). These Fn types are bounds, just like traits (in fact they are traits, as we'll see later). Fn(i32) -> i64 is a bound on the types of all function-like objects with that signature. When we take a reference to a function pointer, we're actually creating a trait object which is represented by a fat pointer (see DSTs).

To pass a function to another function, or to store the function in a field, we must write a type. We have several choices, we can either use either a fn type or a Fn type. The latter is better because it includes closures (and potentially other function-like things), whereas fn types don't. The Fn types are dynamically sized which means we cannot use them as value types. We must either pass function objects or use generics. Let's look at the generic approach first. For example,

fn bar<F>(f: F) -> i64
    where F: Fn(i32) -> i64
{
    f(0)
}

bar takes any function with the signature Fn(i32) -> i64, i.e., we can instantiate the F type parameter with any function-like type. We could call bar(add_42) to pass add_42 to bar which would instantiate F with add_42's anonymous type. We could also call bar(add_41) and that would work too.

You can also pass closures to bar, e.g., bar(|x| x as i64). This works because closure types are also bounded by the Fn bound matching their signature (like functions, each closure has it's own anonymous type).

Finally, you can pass references to functions or closures too: bar(&add_42) or bar(&|x| x as i64).

One could also write bar as fn bar(f: &Fn(i32) -> i64) .... These two approaches (generics vs a function/trait object) have quite different semantics. In the generics case, bar will be monomorphised so when code is generated, the compiler know the exact type of f, that means it can be statically dispatched. If using a function object, the function is not monomorphised. The exact type of f is not known, and so the compiler must generate a virtual dispatch. The latter is slower, but the former will produce more code (one monomorphised function per type parameter instance).

There are actually more function traits than just Fn; there are FnMut and FnOnce too. These are used in the same way as Fn, e.g., FnOnce(i32) -> i64. A FnMut represents an object which can be called and can be mutated during that call. This doesn't apply to normal functions, but for closures it means the closure can mutate its environment. FnOnce is a function which can only be called (at most) once. Again, this is only relevant for closures.

Fn, FnMut, and FnOnce are in a sub-trait hierarchy. Fns are FnMuts (because one can call a Fn function with permission to mutate and no harm is done, but the opposite is not true). Fns and FnMuts are FnOnces (because there is no harm done if a regular function is only called once, but not the opposite).

So, to make a higher-order function as flexible as possible, you should use the FnOnce bound, rather than the Fn bound (or use the FnMut bound if you must call the function more than once).

Methods

You can use methods in the same way as functions - take pointers to them store them in variables, etc. You can't use the dot syntax, you must explicitly name the method using the fully explicit form of naming (sometimes called UFCS for universal function call syntax). The self parameter is the first argument to the method. E.g.,

struct Foo;

impl Foo {
    fn bar(&self) {}
}

trait T {
    fn baz(&self);
}

impl T for Foo {
    fn baz(&self) {}
}

fn main() {
    // Inherent method.
    let x = Foo::bar;
    x(&Foo);
    
    // Trait method, note the fully explicit naming form.
    let y = <Foo as T>::baz;
    y(&Foo);
}

Generic functions

You can't take a pointer to a generic function and there is no way to express a generic function type. However, you can take a reference to a function if all its type parameters are instantiated. E.g.,

fn foo<T>(x: &T) {}

fn main() {
    let x = &foo::<i32>;
    x(&42);
}

There is no way to define a generic closure. If you need a closure to work over many types you can use trait objects, macros (for generating closures), or pass a closure which returns closures (each returned closure can operate on a different type).

Lifetime-generic functions and higher-ranked types

It is possible to have function types and closures which are generic over lifetimes.

Imagine we have a closure which takes a borrowed reference. The closure can work the same way no matter what lifetime the reference has (and indeed in the compiled code, the lifetime will have been erased). But, what does the type look like?

For example,

fn foo<F>(x: &Bar, f: F) -> &Baz
    where F: Fn(&Bar) -> &Baz
{
    f(x)
}

what are the lifetimes of the references here? In this simple example, we can use a single lifetime (no need for a generic closure):

fn foo<'b, F>(x: &'b Bar, f: F) -> &'b Baz
    where F: Fn(&'b Bar) -> &'b Baz
{
    f(x)
}

But what if we want f to work on inputs with different lifetimes? Then we need a generic function type:

fn foo<'b, 'c, F>(x: &'b Bar, y: &'c Bar, f: F) -> (&'b Baz, &'c Baz)
    where F: for<'a> Fn(&'a Bar) -> &'a Baz
{
    (f(x), f(y))
}

The novelty here is the for<'a> syntax, this is used to denote a function type which is generic over a lifetime. It is read "for all 'a, ...". In theoretical terms, the function type is universally quantified.

Note that we cannot hoist up 'a to foo in the above example. Counter-example:

fn foo<'a, 'b, 'c, F>(x: &'b Bar, y: &'c Bar, f: F) -> (&'b Baz, &'c Baz)
    where F: Fn(&'a Bar) -> &'a Baz
{
    (f(x), f(y))
}

will not compile because when the compiler infers lifetimes for a call to foo, it must pick a single lifetime for 'a, which it can't do if 'b and 'c are different.

A function type which is generic in this way is called a higher-ranked type. Lifetime variables at the outer level have rank one. Because 'a in the above example cannot be moved to the outer level, it's rank is higher than one.

Calling functions with higher-ranked function type arguments is easy - the compiler will infer the lifetime parameters. E.g., foo(&Bar { ... }, &Bar {...}, |b| &b.field).

In fact, most of the time you don't even need to worry about such things. The compiler will allow you to elide the quantified lifetimes in the same way that you are allowed to elide many lifetimes on function arguments. For example, the example above can just be written as

fn foo<'b, 'c, F>(x: &'b Bar, y: &'c Bar, f: F) -> (&'b Baz, &'c Baz)
    where F: Fn(&Bar) -> &Baz
{
    (f(x), f(y))
}

(and you only need 'b and 'c because it is a contrived example).

Where Rust sees a function type with a borrowed references, it will apply the usual elision rules, and quantify the elided variables at the scope of the function type (i.e., with higher rank).

You might be wondering why bother with all this complexity for what looks like a fairly niche use case. The real motivation is functions which take a function to operate on some data provided by the outer function. For example,

fn foo<F>(f: F)
    where F: Fn(&i32) // Fully explicit type: for<'a> Fn(&'a i32)
{
    let data = 42;
    f(&data)
}

In these cases, we need higher-ranked types. If we added a lifetime parameter to foo instead, we could never infer a correct lifetime. To see why, let's look at how it might work, consider fn foo<'a, F: Fn(&'a i32')> .... Rust requires that any lifetime parameter must outlive the item it is declared on (if this were not the case, an argument with that lifetime could be used inside that function, where it is not guaranteed to be live). In the body of foo we use f(&data), the lifetime Rust will infer for that reference will last (at most) from where data is declared to where it goes out of scope. Since 'a must outlive foo, but that inferred lifetime does not, we cannot call f in this way.

However, with higher-ranked lifetimes f can accept any lifetime and so the anonymous one from &data is fine and the function type checks.

Enum constructors

This is something of a digression, but it is sometimes a useful trick. All variants of an enum define a function from the fields of the variant to the enum type. For example,

enum Foo {
    Bar,
    Baz(i32),
}

defines two functions, Foo::Bar: Fn() -> Foo and Foo::Baz: Fn(i32) -> Foo. We don't normally use the variants in this way, we treat them as data types rather than functions. But sometimes it is useful, for example if we have a list of i32s we can create a list of Foos with

list_of_i32.iter().map(Foo::Baz).collect()

Closure flavours

A closure has two forms of input: the arguments which are passed to it explicitly and the variables it captures from its environment. Usually, everything about both kinds of input is inferred, but you can have more control if you want it.

For the arguments, you can declare types instead of letting Rust infer them. You can also declare a return type. Rather than writing |x| { ... } you can write |x: i32| -> String { ... }. Whether an argument is owned or borrowed is determined by the types (either declared or inferred).

For the captured variables, the type is mostly known from the environment, but Rust does a little extra magic. Should a variable be captured by reference or value? Rust infers this from the body of the closure. If possible, Rust captures by reference. E.g.,

fn foo(x: Bar) {
    let f = || { ... x ... };
}

All being well, in the body of f, x has the type &Bar with a lifetime bounded by the scope of foo. However, if x is mutated, then Rust will infer that the capture is by mutable reference, i.e., x has type &mut Bar. If x is moved in f (e.g., is stored into a variable or field with value type), then Rust infers that the variable must be captured by value, i.e., it has the type Bar.

This can be overridden by the programmer (sometimes necessary if the closure will be stored in a field or returned from a function). By using the move keyword in front of a closure. Then, all of the captured variables are captured by value. E.g., in let f = move || { ... x ... };, x would always have type Bar.

We talked earlier about the different function kinds: Fn, FnMut, and FnOnce. We can now explain why we need them. For closures, the mutable-ness and once-ness refer to the captured variables. If a capture mutates any of the variables it captures then it will have a FnMut type (note that this is completely inferred by the compiler, no annotation is necessary). If a variable is moved into a closure, i.e., it is captured by value (either because of an explicit move or due to inference), then the closure will have a FnOnce type. It would be unsafe to call such a closure multiple times because the captured variable would be moved more than once.

Rust will do its best to infer the most flexible type for the closure if it can.

Implementation

A closure is implemented as an anonymous struct. That struct has a field for each variable captured by the closure. It is lifetime-parametric with a single lifetime parameter which is a bound on the lifetime of captured variables. The anonymous struct implements a call method which is called to execute the closure.

For example, consider

fn main() {
    let x = Foo { ... };
    let f = |y| x.get_number() + y;
    let z = f(42);
}

the compiler treats this as

struct Closure14<'env> {
    x: &'env Foo,
}

// Not actually implemented like this, see below.
impl<'env> Closure14<'env> {
    fn call(&self, y: i32) -> i32 {
        self.x.get_number() + y
    }
}

fn main() {
    let x = Foo { ... };
    let f = Closure14 { x: x }
    let z = f.call(42);
}

As we mentioned above, there are three different function traits - Fn, FnMut, and FnOnce. In reality the call method is required by these traits rather than being in an inherent impl. Fn has a method call which takes self by reference, FnMut has call_mut taking self by mutable reference, and FnOnce has call_once which takes self by values.

When we've seen function types above, they look like Fn(i32) -> i32 which doesn't look much like a trait type. There is a little bit of magic here. Rust allows this round bracket sugar only for function types. To desugar to a regular type (an 'angle bracket type'), the argument types are treated as a tuple type and passed as a type parameter and the return type as an associated type called Output. So, Fn(i32) -> i32 is desugared to Fn<(i32,), Output=i32> and the Fn trait definition looks like

pub trait Fn<Args> : FnMut<Args> {
    fn call(&self, args: Args) -> Self::Output;
}

The implementation for Closure14 above would therefore look more like

impl<'env> FnOnce<(i32,)> for Closure14<'env> {
    type Output = i32;
    fn call_once(self, args: (i32,)) -> i32 {
        ...
    }
}
impl<'env> FnMut<(i32,)> for Closure14<'env> {
    fn call_mut(&mut self, args: (i32,)) -> i32 {
        ...
    }
}
impl<'env> Fn<(i32,)> for Closure14<'env> {
    fn call(&self, args: (i32,)) -> i32 {
        ...
    }
}

You can find the function traits in core::ops

We talked above about how using generics gives static dispatch and using trait objects gives virtual dispatch. We can now see in a bit more detail why.

When we call call, it is a statically dispatched method call, there is no virtual dispatch. If we pass it to a monomorphised function, we still know the type statically, and we still get a static dispatch.

We can make the closure into a trait object, e.g., &f or Box::new(f) with types &Fn(i32)->i32 or Box<Fn(i32)->i32>. These are pointer types, and because they are pointer-to-trait types, the pointers are fat pointers. That means they consist of the pointer to the data itself and a pointer to a vtable. The vtable is used to lookup the address of call (or call_mut or whatever).

You'll sometimes hear these two representations of closures called boxed and unboxed closures. An unboxed closure is the by-value version with static dispatch. A boxed version is the trait object version with dynamic dispatch. In the olden days, Rust only had boxed closures (and the system was quite a bit different).

References

FIXME: relate to closures in C++ 11