Skip to content

Commit

Permalink
Create binary_tree_node_sum.py
Browse files Browse the repository at this point in the history
  • Loading branch information
ShareCat committed Nov 8, 2023
1 parent 60ad827 commit b946f82
Showing 1 changed file with 76 additions and 0 deletions.
76 changes: 76 additions & 0 deletions algorithm/data_structures/binary_tree/binary_tree_node_sum.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,76 @@
"""
Sum of all nodes in a binary tree.
Python implementation:
O(n) time complexity - Recurses through :meth:`depth_first_search`
with each element.
O(n) space complexity - At any point in time maximum number of stack
frames that could be in memory is `n`
"""


from __future__ import annotations

from collections.abc import Iterator


class Node:
"""
A Node has a value variable and pointers to Nodes to its left and right.
"""

def __init__(self, value: int) -> None:
self.value = value
self.left: Node | None = None
self.right: Node | None = None


class BinaryTreeNodeSum:
r"""
The below tree looks like this
10
/ \
5 -3
/ / \
12 8 0
>>> tree = Node(10)
>>> sum(BinaryTreeNodeSum(tree))
10
>>> tree.left = Node(5)
>>> sum(BinaryTreeNodeSum(tree))
15
>>> tree.right = Node(-3)
>>> sum(BinaryTreeNodeSum(tree))
12
>>> tree.left.left = Node(12)
>>> sum(BinaryTreeNodeSum(tree))
24
>>> tree.right.left = Node(8)
>>> tree.right.right = Node(0)
>>> sum(BinaryTreeNodeSum(tree))
32
"""

def __init__(self, tree: Node) -> None:
self.tree = tree

def depth_first_search(self, node: Node | None) -> int:
if node is None:
return 0
return node.value + (
self.depth_first_search(node.left) + self.depth_first_search(node.right)
)

def __iter__(self) -> Iterator[int]:
yield self.depth_first_search(self.tree)


if __name__ == "__main__":
import doctest

doctest.testmod()

0 comments on commit b946f82

Please sign in to comment.